6 - 6 x 6 = -12

[Itchybottom]

Originally Posted by Rogean [You must be logged in to view images. Log in or Register.]

[Thu Dec 02 18:55:58 2010] You say, '#peval $c->CastToClient()->Message(13, 6 - 6 * 6);'
[Thu Dec 02 18:55:58 2010] -30

The server has spoken.

Must obey.

I'd like to hear the server's thoughts on evaluating:

[You must be logged in to view images. Log in or Register.]

[Rhalous]

Damn, Itchy, gotta clean up that notation, bro.

[teganyavo]

Originally Posted by Itchybottom [You must be logged in to view images. Log in or Register.]

I'd like to hear the server's thoughts on evaluating:

[You must be logged in to view images. Log in or Register.]

how i am supposed to integrate this shit with no dummy variable brew

[Itchybottom]

Originally Posted by teganyavo [You must be logged in to view images. Log in or Register.]

how i am supposed to integrate this shit with no dummy variable brew

Are you trolling, or are you retarded? Either provides amusement.

[Rhalous]

Originally Posted by teganyavo [You must be logged in to view images. Log in or Register.]

how i am supposed to integrate this shit with no dummy variable brew

You can integrate how it's written now. The only thing that is wrong with the notation is a dx on the end.

[teganyavo]

Originally Posted by Rhalous [You must be logged in to view images. Log in or Register.]

You can integrate how it's written now. The only thing that is wrong with the notation is a dx on the end.

I was joking :P dx is a dummy variable

[Daldaen]

Originally Posted by Itchybottom [You must be logged in to view images. Log in or Register.]

I'd like to hear the server's thoughts on evaluating:

[You must be logged in to view images. Log in or Register.]

if you add dx at the end. It becomes:

x^3+0.5x^2-5x .... Evaluated at 0 and 1

0+0+0-[1^+0.5(1)^2-5(1)]
-[1+.5-5]
3.5

[Itchybottom]

Originally Posted by Daldaen [You must be logged in to view images. Log in or Register.]

if you add dx at the end. It becomes:

x^3+0.5x^2-5x .... Evaluated at 0 and 1

0+0+0-[1^+0.5(1)^2-5(1)]
-[1+.5-5]
3.5

Thread winner!

[Ishio]

Yay, I was the first one who was right!

[Daldaen]

Combine the Taylor Series expansion of the Cosine and Sine functions and take the absolute value of its sum. Which function does this Taylor Series expansion resemble? This blew my mind the first time I saw it.