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#1
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Quote:
As for the OP comment, there is a slight chance that a stone does not drop in any 53 hour period. The calculation is (1-0.05)^(53*60/28) = 0.00295 = 0.3% chance. | |||
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#2
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at least from whats been reported, is it confirmed 60% spawn chance? certainly never felt THAT common, many times 4+ hours of only frogs.
__________________
Eratani / Cleratani / Eratou / Stabatani / Flopatani / Eratii
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#3
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It may be that it is 60% with an 8% drop rate. This produces a 4.8% probability of a stone every 28 minutes, which is really close to the 5% stated earlier. Can anyone produce better spawn and/or drop rates? | |||
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#4
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Quote:
https://www.project1999.com/forums/s...d.php?t=342763
__________________
Eratani / Cleratani / Eratou / Stabatani / Flopatani / Eratii
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#5
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We have about 150 days until they are removed with the Sol Ro patch in May 2020 Let's be even more generous and round up to 2 manastones per day. That means only 300 more people (per server) can get a manastone before they are removed. Ouch... | |||
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#6
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Quote:
If we do the calculation again, we get (1-0.033)^(53*60/28) = 2.2% chance. So there is a 1-in-45 chance of a manastone NOT dropping in any 53 hour period. | |||
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#7
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When you look at it that way rather than 1/X EE drop it, pretty depressing.
__________________
Eratani / Cleratani / Eratou / Stabatani / Flopatani / Eratii
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#8
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From the Ataria data, there were 57 EE for 152 attempts, so that's 37.5% Let's assume 30% chance of an EE pop.
In those 57 pops, 5 stones dropped which is 8.8%. Let's assume there is a 10% chance of a manastone when the EE pops. So the chance of a manastone dropping is 10% of 30%, or 0.10 x 0.30, which is 3%. I think after all of our discussion, this is a pretty good estimate of the drop rate of a manastone at any 28 minute interval. If we incorporate the binomial distribution, the chance of x manastones dropping in n attempts is: P(x) = n(C)x * (0.97)^(n-x) * (0.03)^(x) where n(C)x = n!/((n-x)!*x!) So the probability of 5 manastones dropping in 152 attempts is: P(5) = 152(C)5 * (0.97)^(152-5) * (0.03)^(5) = 17.5%. Since there are around 51 attempts in a day, here are the probabilities of the various amounts of manastones dropping within a 24 hour period: P(0) = 51(C)0 * (0.97)^(51) * (0.03)^(0) = 21.2%. P(1) = 51(C)1 * (0.97)^(50) * (0.03)^(1) = 33.4%. P(2) = 51(C)2 * (0.97)^(49) * (0.03)^(2) = 25.8%. P(3) = 51(C)3 * (0.97)^(48) * (0.03)^(3) = 13.0%. P(4) = 51(C)4 * (0.97)^(47) * (0.03)^(4) = 4.8%. P(5) = 51(C)5 * (0.97)^(46) * (0.03)^(5) = 1.4%. P(6) = 51(C)6 * (0.97)^(45) * (0.03)^(6) = 0.3%. Therefore, the expected number of manastones in a 24 period would be 1.522. | ||
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