Quote:
Originally Posted by reddi lol
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Idiot
Such an issue is valid since the divergence of an electro- magnetic energy-stress tensor ∇c T(E)cb (where ∇c is a co- variant derivative) generates only the Lorentz force, whereas the divergence of a massive energy-stress tensor ∇c T (m)cb would generate the geodesic equation [9].
Thus, the energy-stress of photons T (L)ab would be T(L)ab =T(E)ab +T(N)ab (1)
or
T(N)ab =T(L)ab −T(E)ab
where T (E )ab and T (N )ab are respectively the electromag- netic energy-stress tensor and a non-electromagnetic energy- stress tensor. Besides, being intrinsically traceless, T(E)cb would not be compatible with Einstein’s formula △E = =△mc2. Based on the fact that the electromagnetic energy is dominating experimentally, it is natural to assume as shown later that T(N)ab is in fact the gravitational energy-stress tensor T (g)ab .
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you're talking about delta ΔEnergy of mass-energy equivalence not being provable because light cannot travel through a perfect medium (it talks about interference from electromagnetic radiation and the effects of universal gravitation on the photons but completely ignores dark matter). this while fascinating insight is clearly not what the picture demonstrates
If you look carefully at it the man is showing how different angles have the same Θ's from a set of linear equations. The nullity of the distribution of vectors in the elementary matrices has row vectors which span the system, proving the nullity is 0 so the determinant cannot be 0. From that we know then that λ=0 is not an eigenvalue for the matrix formed by the eigenvalues which can be diagonalized. The distributons and norms can be used in the Grahm Schmidt process since the rank of the geometic and algebraic dimensions are equal. And upon further reflection I will say the inner Euclidian product space is formed of an orthonormal basis, I knew it was orthogonal as I stated prior, but it is definitely orthonormal as well as Grahm Schmidt process dictates