[Estu]

Originally Posted by sambal [You must be logged in to view images. Log in or Register.]

I don't think you're 100% correct here.

The skeleton is drawing from the possibility of dropping two bones, each with the probability of 50%. This is the way almost every video game works, which does wind up yielding a normal distribution. It's much easier for the server to compute these straightforward loot tables, and appear to be convoluted to the player.

p_Bone_A = 0.5
p_Bone_B = 0.5

Probability that bone_A does not drop, P(A'):........................... 0.5 (no bone_A, irrespective of bone_B)
Probability that bone_B does not drop, P(B'):........................... 0.5 (no bone_B, irrespective of bone_A)
Probability that bone_A or bone_B drops, but not both:............. 0.5 (one bone)
Probability that bone_A and bone_B both drops, P(A∩B):............ 0.25 (two bones)
Probability that bone_A and/or bone_B drops, P(A∪B):............... 0.75 (one or two bones)
Probability that neither bone_A or bone_B drops, P(A'∩B'):.......... 0.25 (zero bones)

How is this different from what I said?