Quote:
Originally Posted by Nubben
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In the above game there is no proper betting strategy. The game is basically the same as flipping a coin. If you play it enough times, you and the house will both break even.
Using a bet of 100 to keep the math simple:
57.5% of the time (1 to 574) you will lose 100.
32.5% of the time (575 to 899) you will win 100.
7.5% of the time (900 to 974) you will win 200.
2.5% of the time (975 to 1000) you will win 400.
So each time you bet 100 you will win
(-100*.575) = -57.5
(100*.325) = 32.5
(200*.075) = 15
(400*.025) = 10
(-57.5+32.5+15+10) = 0
This math remains the same no matter what your bet is.
Basically, this game is a big waste of time unless you like betting on coin flips. You might as well just run a casino that is /random 1 2 where a 1 you lose and a 2 you win, you'll end up with the same results in the long run.
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True, but you're not accounting for instances where you just win 100 and start over, or you win 900+ and make money. Just like playing BJ where you make all of your money from doubling down and hitting BJ, not beating the dealer. Also, if your math is correct this would increase your odds from .435% to .50%. Seems good to me!