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Old 07-31-2023, 12:27 PM
Origen Origen is offline
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Join Date: Jun 2023
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Quote:
Originally Posted by Landroval [You must be logged in to view images. Log in or Register.]
Attachment 22472

Let v = c
Y = √(1-c^2/c^2)
Y = √(1-1)
Y = √(0)
Y = undefined; omnipresence
From the perspective of the photon as it "looks out" into the universe, it is surrounded by all-mass exactly 0 distance from it.

Assuming a photon with infinite energy potential (infinite hertz frequency) calculate the mass of the photon:

E^2 = (mc^2)^2 + pc^2
Because it is surrounded by all mass and distance doesn't exist it has no momentum; therefore p = 0

E^2 = (mc^2)^2
√E^2 = √(mc^2)^2
E = mc^2
E = infinity; c=infinite velocity
Therefore
(Infinity) = m(infinity^2)
Solve for m
m = (infinity)/(infinity^2)
m = 1/infinity

Photons are not massless. Proof "The Science" is errant
Solar sails wouldn't work if photons had no mass, and this isn't how science works anyways.

Badly refuting something you have probably misunderstood in unrelated particle physics doesn't change the nature of other data