e0f911_abc202da8792412a9d2f24bd86d4da4f~mv2.png
Let v = c
Y = √(1-c^2/c^2)
Y = √(1-1)
Y = √(0)
Y = undefined; omnipresence
From the perspective of the photon as it "looks out" into the universe, it is surrounded by all-mass exactly 0 distance from it.
Assuming a photon with infinite energy potential (infinite hertz frequency) calculate the mass of the photon:
E^2 = (mc^2)^2 + pc^2
Because it is surrounded by all mass and distance doesn't exist it has no momentum; therefore p = 0
E^2 = (mc^2)^2
√E^2 = √(mc^2)^2
E = mc^2
E = infinity; c=infinite velocity
Therefore
(Infinity) = m(infinity^2)
Solve for m
m = (infinity)/(infinity^2)
m = 1/infinity
Photons are not massless. Proof "The Science" is errant